\(the\ variation\ without\ repetition:\\\\P(n;k)= \frac{\big{n!}}{\big{(n-k)!}} \\\\---------------------\\\
=9\ \ \ and\ \ \ k=5\\\\\Rightarrow\ \ \ P(9;5)=\frac{\big{9!}}{\big{5!}}=\frac{\big{5!\cdot6\cdot7\cdot8\cdot9}}{\big{5!}}=3024\\\\Ans.\ there\ are\ 3024\ ways\ to\ choose.\)
