what is an equation of the parabola with vertex at the origin and focus (-6, 0)?
Hello,
p is the parameter of the parabola
y²=2px is his equation.
Focus F=(p/2,0)
Directrice x=-p/2
Here p/2=-6==>p=-12
Equation is y²=-24x
Answer:
\(y^{2}=-24x\)
Step-by-step explanation:
According to analytic geometry, a parabola is define as
\(y^{2}=4px\)
Where \(p\) is the coordinate of the focus.
So, the equation for this parabola is
\(y^{2}=4(-6)x\)
\(y^{2}=-24x\)
The negative sign indicates that the parabola opens leftward. The image attached shows the graph.