The slope of the first line is \(m_1=\frac{-1}{3}\).
To be perpendicular the slope of the second line must be the negative reciprocal of the first: \(m_2=3\)
Use the slope-intercept formula:
\(y=mx+b\)
Substitute known values:
\(12=3(3)+b\)
Solve for \(b\):
\(b=3\)
Complete the formula:
\(y=3x+3\)
