A piston above liquid in a closed container has an area of 1m2. The piston carries a load of 350 kg. What will be the external pressure on the upper surface of the liquid in KPA
Pressure = force / area
I assume that 350kg is the mass
Therefore,
350 x 9.8 (gravity) = 3430N
3430 / 1 = 3430Pa
3.43 KPa
Answer:
3.43 kPa
Explanation:
Pressure is defined as the ratio between the force applied and the area of the surface on which the force is applied:
\(p=\frac{F}{A}\)
in this problem, the force corresponds to the weight of the load, which is given by the product between its mass (350 kg) and the acceleration due to gravity (9.8 m/s^2):
\(F=mg=(350 kg)(9.8 m/s^2)=3430 N\)
And since the area on which this force is applied is \(A=1 m^2\), the pressure exerted on the upper surface of the liquid is
\(p=\frac{F}{A}=\frac{3430 N}{1 m^2}=3430 Pa = 3.43 kPa\)