What is the simplified form of the following expression? Assume $y
eq 0$.
$\sqrt[3]{\frac{12 x^2}{16 y}}$
A$\frac{2\left(\sqrt[3]{6 x^2 y^2}\right)}{y}$
B$\frac{\sqrt[3]{12 x^2 y}}{2 y}$
C$\frac{x(\sqrt[3]{3 y})}{2 y}$
D$\sqrt[3]{6 x^2 y^2}$
eq 0$.
$\sqrt[3]{\frac{12 x^2}{16 y}}$
A$\frac{2\left(\sqrt[3]{6 x^2 y^2}\right)}{y}$
B$\frac{\sqrt[3]{12 x^2 y}}{2 y}$
C$\frac{x(\sqrt[3]{3 y})}{2 y}$
D$\sqrt[3]{6 x^2 y^2}$