Answer:
(D)
Step-by-step explanation:
The quadratic equation is in the form :
\((x+p)(x+q)\)
\(x^2+px+qx+pq\)
\(x^2+(p+q)x+pq\)
and In the above, (p + q) = b and pq = c.
To factor a quadratic, we'll need to start by finding the two numbers (being the p and the q above) that add up to equal b, where those numbers also multiply to equal c.
Since, both 3 and 5 in the given equation \(3x^2+5x+1\) are prime numbers, thus the given equation cannot be factorised because of the prime nature.
Hence, option D is correct.
