xy=2
x+y=-2
minus x
y=-2-x
sub
x(-2-x)=2
-2x-x^2=2
add 2x+x^2 both sides
0=x^2+2x+2
quadratic formula
if you have
ax^2+bx+c=0
x=\(\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}\)
x^2+2x+2
a=1
b=2
c=2
x=\(\frac{-2+/- \sqrt{2^{2}-4(1)(2)} }{2(1)}\)
x=\(\frac{-2+/- \sqrt{4-8} }{2}\)
x=\(\frac{-2+/- \sqrt{-4} }{2}\)
x=\(\frac{-2+/- \sqrt{-1}\sqrt{4} }{2}\)
remember √-1=i
x=\(\frac{-2+/- i\sqrt{4} }{2}\)
x=\(\frac{-2+/- 2i}{2}\)
x=-1+/-i
x=i-1 or -i-1
the 2 numbers are i-1 and -i-1
