solve for x m<AOB =4x-2,m<BOC=5x+10,m<COD=2x+14
what you have to do is solve for x of course stated above4x - 2 + 5x + 10 = 2x +14 9x +8 = 2x + 14(minus 2x from both sides)7x + 8 = 14(minus 8 from both sides)7x = 7(divide 7 from both sides)x=1
Answer:
Its not one because 14-8 is not 7 its 6.
Step-by-step explanation: