(26 m/s)(1 rotation/0.62π m) ≈ 13.35 rotations/s that will do pig that'll do
Explanation :
It is given that,
The diameter of the car's diameter, d = 0.62 m
Radius, r = 0.31 m
Speed of the car, v = 20 m/s
We know that the relation between the angular velocity and linear velocity is given by :
\(v=r\omega\)
Where \(\omega\) is angular velocity
\(\omega=\dfrac{v}{r}\)
\(\omega=\dfrac{20\ m/s}{0.31\ m}\)
\(\omega=64.5\ rotations/sec\)
Hence, this is the required solution.