To solve we need to use Pythagoras theorem ( \(a^{2} + b^{2} = c^{2}\) )
There are 2 possible lengths for x: hypotenuse or one of the 2 shorter sides.
Hypotenuse:
10^{2} + 21^2 = \(x^{2}\)
100+441= \(x^{2}\)
\(\sqrt{541} = \sqrt{ x^{2} }\)
23.3≈x
Shorter leg:
\(10^2 + x^2=21^2\)
\(x^2= 21^2-10^2\)
\(x^{2}\)= 441-100
\(\sqrt{ x^{2} } = \sqrt{341}\)
x≈18.47
