MathSpecialist1
Answered

Frank has two same size rectangles divided into the same number of equal parts. One rectangle has 3/4 fourths of the parts shaded and the other has 1/3 third of the parts shaded.


Part A

Into how many parts could each rectangle be divided?


Part B


Is there more than possible answer to Part A? If so find the least number of parts in which bot rectangles could be divided? EXPLAIN your reasoning.

Verified Answer :

Both rectangles need to be divided into a number of of parts that is divisible into both 3 and 4 parts. Since 3 and 4 don't have any factors  in common, it has to be divisible by both 3 and 4, so it has to have minimally 3*4=12 parts (answer to A and B!) but it can be any multiplication of 12, such as 24, 36, etc. 

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