how do i solve 25=7+3k-12
\(25=7+3k-12\ \ \ \ \ free\ numbers\ on\ the\ left\ x's\ on\ the\ right\\25-7+12=3k\\30=3k\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |:3\\k=10\)
\(25=7+3k-12\\ 3k=30\\ k=10\)