\(x^{2} - 3x - 5 = 0 \\ \\ \Delta = (-3)^{2} - 4 \cdot 1 \cdot (-5) = 9 + 20 = 29 \\ \\ \sqrt{\Delta } = \sqrt{29} \\ \\ x_{1} = \dfrac{3 - \sqrt{29} }{2} \\ \\ x_{2} = \dfrac{3+ \sqrt{29} }{2} \\ \\ \boxed{x \in \left \lbrace \dfrac{3 - \sqrt{29} }{2} , \dfrac{3 + \sqrt{29} }{2} \right \rbrace }\)
