Verified Answer :

Answer:

\(A(1)=-5\times2^1-1=-11\)

\(A(1)=-5\times2^4-1=-81\)

\(A(1)=-5\times2^8-1=-1281\)

Step-by-step explanation:

Given :     \(A(n)=-5\times2^n-1\)


To find :   \(A(1), A(4), A(18)\)


Solution:

Put n=1, \(A(1)=-5\times2^1-1\)

               \(A(1)=-10-1=-11\)


Put n=4, \(A(1)=-5\times2^4-1\)

                \(A(1)=-80-1=-81\)

Put n=8, \(A(1)=-5\times2^8-1=\)

               \(A(1)=-1280-1=-1281\)

JeanaShupp

Answer: \(A(1)=-5\)

\(A(4)=-40\)

\(A(8)=-640\)

Step-by-step explanation:

Given sequence : \(A(n)=-5\times2^{n-1}\)

To find the first term, we need to put n=1 in the above sequence , we get

\(A(1)=-5\times2^{1-1}=-5\times2^0=-5\)

To find the fourth term, we need to put n=4, we get

\(A(4)=-5\times2^{4-1}=-5\times2^3=-5\times8=-40\)

To find the eighth term, we need to put n=8, we get

\(A(8)=-5\times2^{8-1}=-5\times2^7=-5\times128=-640\)

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