NathalyN
Answered

I REALLY NEED NEED HELP IT DOSENT NEED TO BE A BIG PROCESS A LITTLE ONE!!!!

  1. Think of another quadratic equation that has two (2) real number solutions. Write the

equation in ax^2 + bx + c = 0 form. Then find the value of the discriminant to support your

answer.

  1. Think of another quadratic equation that has one (1) real number solution. Write the

equation in ax^2 + bx + c = 0 form. Then find the value of the discriminant to support your

answer.

  1. Think of another quadratic equation that has no (0) real number solutions. Write the

equation in ax^2 + bx + c = 0 form. Then find the value of the discriminant to support your

answer.

Verified Answer :

Bananapus

  1. -2x^2+6x+3=0
    -2x^2+6x+     = -3
    -2x^2+6x
    36/4=9
    (-2x^2+6x+9)^2= -3-9
    (-2x+9)^2= -12
    (-2x)^2= -12-9
    (-2x)^2= -18
    x= square root of  9


    10.  same thing above, but not a -2.  if you use +2 the answer will be square root of -9. 








Kytten

8.)  x^2 + 7x + 12 = 0, a = 1, b = 7, c = 12, discriminant = b^2 - 4ac = (7)^2 - 4(1)(12) = 1, discriminant > 0 indicates two solutions.

9.) x^2 + 4x + 4 = 0, a = 1, b =4, c =4, discriminant = b^2 - 4ac = (4)^2 - 4(1)(4) = 0, and discriminant = 0 indicates one solution.

10.) x^2 + 1 = 0, a = 1, b =0, c = 1, discriminant = b^2 - 4ac = 0^2 - 4(1)(1) = -4, and discriminant < 0 indicates no real solution.

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