Solve for x: -2(x + 3) = -2(x + 1) - 4
\(-2(x + 3) = -2(x + 1) - 4\\ -2x-6=-2x-2-4\\ -6=-6\\ x\in\mathbb{R}\)
\(-2(x+3)=-2(x+1)-4\\\\-2x-6=-2x-2-4\\\\-2x-6=-2x-6\ \ \ \ |add\ (-2x)\ to\ both\ sides\\\\-6=-6\ \ TRUE\\\\ infinitely\ many\ solutions,\ x\in\mathbb{R}.\)
