solve 2y - 5 over 3 = 4y - 1 over 2
\(\frac{2y - 5}{3} = \frac{4y - 1}{2}\)\(3(4y - 1) = 2(2y - 5)\)\(3(4y) - 3(1) = 2(2y) - 2(5)\)\(12y - 3 = 4y - 10\)\(8y - 3 = -10\)\(8y = -7\)\(\frac{8y}{8} = \frac{-7}{8}\)\(y = -0.875\)