Answer:
The slope of the line is \(-\frac{2}{3}\)
Step-by-step explanation:
For any line \(y=mx+b\), a line that is perpendicular to it is \(y_\perp =-\frac{1}{m} x+b\).
Therefore the slope of the perpendicular line is \(-\frac{1}{m}\).
For our case \(y=\frac{3}{2}x-\frac{1}{2}\) therefore the slope of the prependicular is the reciprocal of \(\frac{3}{2}\) multiplied by \(-1.\)
\(\therefore\:slope=-\frac{2}{3}.\)
