so the points are (-3/7,-8/3) and (-5/2,-2)
to find the slope do
(y2-y1)/(x2-x1)
(x,y)
x1=-3/7
y1=-8/3
x2=-5/2
y2=-2
subsitute
\(\frac{-2-( \frac{-8}{3} )}{ \frac{-5}{2} - \frac{-3}{7} }\)
simplify by finding similar denomenators
\(\frac{\frac{-6}{3}-( \frac{-8}{3} )}{ \frac{-35}{14} - \frac{-6}{14} }\)
\(\frac{\frac{-6}{3}( \frac{8}{3} )}{ \frac{-35}{14} + \frac{6}{14} }\)
add
\(\frac{\frac{2}{3}}{ \frac{-29}{14}}\)
multiply top and bottom by \(\frac{-14}{29\)
\(\frac{\frac{-28}{87}}{1}\)
\(\frac{-28}{87}\)
answer is
slope=\(\frac{-28}{87}\)
