\(\frac{1}{4}\) of 2340
= \(\frac{1}{4}\) × 2340
= 585 (this is the total number of seniors)
\(\frac{1}{6}\) of 2340
= \(\frac{1}{6}\) × 2340
= 390 (this is the total number of sophomores)
585 + 390 = 975 (this is the total of sophomores and seniors)
Therefore the number of freshmen & juniors must be
2340 - 975
= 1365
