Given:
Length of rectangle = 2 meters
Width of rectangle = 1.5 meters.
Diameter of semicircle = 2 meters
I am assuming that the diameter of the semicircle is attached to one of the length of the rectangle.
Perimeter of the rectangle part of the table is = 2 + 1.5 + 1.5 = 5 meters
Perimeter of the semicircle = 1/2 π d + d = 1/2 3.14 2 + 2
= 3.14 + 2
= 5.14 meters
Perimeter of the office table: 5 meters + 5.14 meters = 10.14 meters.
