Answer:
\(3x^2-14x+14\)
Step-by-step explanation:
the expression we have is:
\(3(x-2)^2-2(x-1)\)
to solve we need to develop the square binomial
\((x-2)^2\)
with the following formula:
\((a-b)^2=a^2-2ab+b^2\)
So we have:
\((x-2)^2=x^2-2*2x+2^2\\(x-2)^2=x^2-4x+4\)
and the expression now is:
\(3(x^2-4x+4)-2(x-1)\)
developing multiplications to remove parentheses:
\(3x^2-3*4x+3*4-2x+2*1\\3x^2-12x+12-2x+2\)
joining like terms:
\(3x^2-14x+14\)
