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flirtmcfelt flirtmcfelt
  • 15-08-2014
  • Mathematics
Answered

12-[20-2(6^2/3•2^2)]

Verified Answer :

Anonymous Anonymous
  • 15-08-2014

12-[20-2(6²/32²)]

=12-[20-2(36/3
4)]

=12-[20-2(12*4)]

=12-[20-2(48)]

=12-[20-96]

=12-(-76)

=12+76

=88

Answer Link
kate200468
kate200468 kate200468
  • 16-08-2014

\(12-\bigg{[}20-2\cdot \bigg{(} \frac{\big{6^2}}{\big{3}} \cdot2^2\bigg{)}\bigg{]}=12-\bigg{[}20-2\cdot \bigg{(} \frac{\big{36}}{\big{3}} \cdot4\bigg{)}\bigg{]}=\\\\=12-(20-2\cdot 12 \cdot4)=12-(20-96)=12-(-76)=12+76=88\)

Answer Link

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