7 copies of the sum of 8 fifths and 4
Answer:
39.2
Step-by-step explanation:
We need to find the solution of 7 copies of sum of 8 fifths and 4.
Now, 8 fifths = \(\frac{8}{5}\)
Then, sum of 8 fifths and 4 = \(\frac{8}{5}+4\) = \(\frac{28}{5}\)
Now, 7 copies of \(\frac{28}{5}\) means that we meed to multiply \(\frac{28}{5}\) 7 times
i.e. 7 copies = \(7\times \frac{28}{5}\)
i.e. 7 copies = \(\frac{196}{5}\)
i.e. 7 copies = 39.2
Hence, 7 copies of sum of 8 fifths and 4 is 39.2
39¹/₅ or 39.2
The Problem:
The Process:
Here are some early expressions that need attention.
7 copies of the sum of 8 fifths and 4 mean that we have to multiply 7 with the sum of 8 fifths and 4. The term of "the product" is synonymous with multiplication.
Let us write an expression to match for '7 copies of the sum of 8 fifths and 4'.
\(\boxed{\boxed{ \ 7 \times \bigg(\frac{8}{5} + 4 \bigg) \ }}\)
Let us calculate the operation in parentheses at first.
\(\boxed{ \ \frac{8}{5} + 4 \ }\)
\(\boxed{ \ \frac{8}{5} + \frac{20}{5} \ }\)
\(\boxed{ \ \frac{28}{5} \ }\)
And now we solve the full expression.
\(\boxed{ \ = 7 \times \bigg(\frac{8}{5} + 4 \bigg) \ }\)
\(\boxed{ \ = 7 \times \frac{28}{5} \ }\)
\(\boxed{\boxed{ \ \frac{196}{5} \ }}\)
In mixed fraction:
\(\boxed{ \ \frac{196}{5} = \ ? \ }\)
\(\boxed{ \ = \frac{195}{5} + \frac{1}{5} \ }\)
\(\boxed{ \ = 39 + \frac{1}{5} \ }\)
\(\boxed{\boxed{ \ 39\frac{1}{5} \ }}\)
In decimal:
\(\boxed{ \ 39\frac{1}{5} = \ ? \ }\)
\(\boxed{ \ = 39\frac{1 \times 2}{5 \times 2} \ }\)
\(\boxed{ \ = 39\frac{2}{10} \ }\)
\(\boxed{\boxed{ \ 39.2 \ }}\)
Thus, the result is \(\boxed{\boxed{ \ 39\frac{1}{5} \ or \ 39.2 \ }}\).
Keywords: what, 7 copies, the sum of, 8 fifths and 4, write an expression to match, and then evaluate, 39¹/₅ or 39.2, multiply, parentheses, in mixed fraction, decimal
