Write two expressions where the solution is 41
\(5^2+4^2=25+16=41\\\\5\cdot8+1=40+1=41\)
\(\frac{31-11}{2}\times4+1=\frac{20}{2}\times4+1=10\times4+1=40+1=41\\\\(2+4)^2+2^2+(123\times298)^0=6^2+4+1=36+4+1=41\)
