\(f(x)+g(x)=x^3+2x^2+3x^2-1=x^3+5x^2-1\\
D:x\in\mathbb{R}\)
\(f(x)-g(x)=x^3+2x^2-(3x^2-1)=x^3+2x^2-3x^2+1=x^3-x^2+1\\
D:x\in\mathbb{R}\)
\(f(x)\cdotg(x)=(x^3+2x^2)(3x^2-1)=3x^5-x^3+6x^4-2x^2=\\
3x^5+6x^4-x^3-2x^2\\
D:x\in\mathbb{R}\)
\(\frac{f(x)}{g(x)}=\frac{x^3+2x^2}{3x^2-1}\\
3x^2-1
ot=0\\
3x^2
ot=1\\
x^2
ot=\frac{1}{3}\\
x
ot =-\frac{\sqrt3}{3} \wedge x
ot =\frac{\sqrt3}{3}\\
D:x\in(-\infty,-\frac{\sqrt3}{3} )\cup(\frac{\sqrt3}{3} ,\infty)\)
