If a woman is homozygous for type A blood and her husband is type O, what is the probability that their offspring would have any one of the 4 possible blood types.

The four blood types are A, B, AB and OThe probability that their offspring would have A blood type is 100%. Since one of the parents is homozygous for type A blood while the other is type O

The probability that their offspring would have B blood type is zero (0) since neither of the parents have B antigene

The probability that their offspring would have AB blood type is zero (0) since neither of the parents have B antigene.

The probability that their offspring would have B blood type is zero (0) since only one of the parents have O antigene. The other parent is homozygous for type A, which means the antigens are AA.

JoiePatel JoiePatel · Answer 2 · 2018-12-10T00:18:46-05:00

Answer:

The offspring would have type A blood group.

The genotype of mother would be \(I^{A}I^{A}\) (homozygous type A blood group).

Thus, she will produce only one type of gamete that is, \(I^{A}\).

Similarly, the genotype of a the father would be ii (type O blood group).

He will also produce only one type of gamete that is, i.

The cross would produce offspring with genotype \(I^{A}i\).

Thus, the offspring would have only type A blood group.

Hence, the probability of having blood group A would be 100% and probability of having other blood group (B, AB or O) would be zero %.