Verified Answer :

\(S_A=\frac{1}{2}LP+B\\\\\frac{1}{2}LP+B=S_A\ \ \ \ \ \ |subrtact\ "B"\ from\ both\ sides\\\\\frac{1}{2}LP=S_A-B\ \ \ \ \ |multiply\ both\ sides\ by\ 2\\\\LP=2S_A-2B\ \ \ \ \ \ |divide\ both\ sides\ by\ "L"\\\\P=\frac{2S_A-2B}{L}\)

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