Verified Answer :

21 inch³ is the answer hope this helps

Answer:

21 cubic inches is the volume of a box that will hold exactly 567 of these cubes with 1/3 inch sides.

Step-by-step explanation:

Given: number of cubes(n) = 567 and sides of cubes = \(\frac{1}{3}\) inch.

Volume of cubes states it is found by multiplying the length of any edge by itself twice i,e

Volume of cubes(V) = \(a^3\)      where a is the sides of the cubes.

then;

Volume of each cubes = \((\frac{1}{3})^3 = \frac{1}{27}\) cubic inches.

Since, the box that will hold exactly 567 of these cubes.

⇒Volume of box = n \(\times\) volume of each cubes.

Substitute the given values we get;

Volume of a box = \(567 \times \frac{1}{27} = 21\) cubic inches.

Therefore, volume of a box that will hold exactly 567 of these cubes with 1/3 inch sides is, 21 cubic inches.