Solve the linear system using substitution or elimintation. 3x-2y=-5, 4x+5y=47
{ 3 x - 2 y = - 5 ( 4 ) ( I )
4 x +5 y = 47 ( -3 ) (II)
12 x - 8 y = - 20
-12 x - 15 y = -141
--------------------------
- 23 y = -161 ( - 1 )
23 y = 161
y = 161 / 23
y = 7
For x
3 x - 2 y = - 5 ( I )
3 x - 2 7 = - 5
3 x - 14 = - 5
3 x = - 5 + 14
3 x = 9
x = 9 / 3
x = 3
Solution:
x = 3 and y = 7
Hope this helps!.