a bag contains 6 red marbles, 2 white marbles, and 1 gray marble. you randomly pick out a marble, record its color, and put it back in the bag. you repeat this process 45 times. how many white or gray marbles do you expect to get
since gray and white make up 1/3 of the bag, (2+1+6=9 ; 2+1=3 ; 3/9=1/3) then then the answer would be 1/3 of 45, which is 15
Answer:
15 white or gray marbles
Step-by-step explanation:
Be
A = 6 red marbles
B = 2 white marbles
C = 1 gray marble
R = 45 process repetition
T = 6 + 2 + 1 = 9 Total marbles
P (B U C) = Possibility of obtaining white or gray marbles once
The probability of an event is calculated by dividing the number of successes by the total possibilities, in this case that is
\(P(B)=\frac{2}{9}\)
\(P(C)=\frac{1}{9}\)
\(P(B U C)=\frac{2}{9}+\frac{1}{9}=\frac{3}{9}=\frac{1}{3}\)
As the process is repeated 45 times, the possibility of obtaining white or gray marbles is the multiplication of
\(45*\frac{1}{3}=15\) white or gray marbles
Hope this helps!