The exponent form of 343 using 7 as base will be \(7^3\).
Given value is 343.
We have to express it with an exponent.
An exponent refers to the number of times a number is multiplied by itself.
Now, the factors of 343 is ,
\(343=7\times7\times7\)
Since the base is same ( 7 ) here, so applying the identity \(x^{m} \times x^{n} =x^{m+n}\)
So,
\(343=7^{1+1+1}\)
\(343=7^{3}\)
Hence the exponent form of 343 is \(7^3\).
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