Answer:
\(6.83.10^{-3} mol FeCl_{3}\)
Explanation:
We have to find the molar mass of the compound.
We must multiply the atomic mass of each element of the compound by the number of atoms of each one
\(FeCl_{3}\)
molar mass \(FeCl_{3}\)
\(Fe= 56g/mol\\Cl= 35g/mol\)
\(FeCl_{3}= 56g/mol+3(35g/mol)=161g/mol\)
We know that in 1 mol of \(FeCl_{3}\) it has a mass of 161g.
Now we can find out how many moles of \(FeCl_{3}\) are in 1.1 g.
\(161g FeCl_3\longrightarrow 1 mol FeCl_3\\ 1.1g FeCl_3\longrightarrow x\\ x=\frac{1.1g FeCl_3.1 molFeCl_3}{161 g FeCl_3} = 6.83.10^{-3} mol FeCl_{3}\)
