\(\left \{ {{x-4y=5} \atop {x=3y-2}} \right.\)
subsititute x = 3 y - 2
[ 3 y - 2 - 4 y = 5 ]
3 y - 2 - 4 y = 5
3y - 4y = 5 + 2
-y = 7 * ( -1 )
y = -7
For x = 3 y - 2
subsititute y = - 7
x = 3 y - 2
x = 3 . ( - 7 ) - 2
x = - 21 - 2
x = - 23
hope this helps!.
