Answered

Calculate the kinetic energy of a particle with a

mass of 3.34 × 10^–27 kilogram and a speed of

2.89 × 10^5 meters per second. [Show all work,

including the equation and substitution with

units.]

Verified Answer :

naccy

K=1/2×mv²
m=3.34×10^-27
V=2.89×10^5
k=1/2 × 3.34×10^-27 ×  (2.89×10^5)²= 1/2 ×3.34×10^-27 × 8.3521×10^10=
1/2 × 27.9 × 10^-17=  13.95 × 10^-17 joule

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