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Tickets to a play cost $5 at the door and $4 in advance. The theater club wants to raise at least $400 from the play. Write and graph an inequality for the number of tickets the theater club needs to sell. If the club sells 40 tickets in advance, how many tickets do they need to sell at the door to reach their goal?

Please help and show how to do this work. Thank you!

Verified Answer :

sparklyypillss

Answer:


Step-by-step explanation:

Let us notice that the questioner had put the words "at least" in their problem; so this would be an inequality problem.

Let us say x represents the number of tickets sold at the door and y is the number of tickets sold in advance.

If this is so, your problem should be;

5x+4(40)≥400

1. Distribution; 5x+160≥400

2. Subtract 160 from both sides; 5x+160-160≥400-160

3. you are left with; 5x≥240

4. divide 5 from both sides; 5x/5≥240/5

5. you are left with; x ≥ 48

Meaning; they need to sell 48 or more tickets at the door to reach their goal of $400.

fichoh

Using system of equation to represent the scenario, the number of tickets that should be sold at the door to meet the inequality condition is 48 tickets.

Let ;

  • Number of door tickets = x
  • Number of advance tickets = y = 40

Creating a system of equations :

  • 5x + 4y ≥ 400 - - - - - - - - (1)

5x + 4(40) ≥ 400

5x + 160 ≥ 400

5x ≥ 400 - 160

5x ≥ 240

x ≥ 48

Therefore, they need to sell 48 tickets at the door.

Learn more : https://brainly.com/question/18796573

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