Answered

On a small planet, an astronaut uses a vertical

force of 175 newtons to lift an 87.5-kilogram

boulder at constant velocity to a height of

0.350 meter above the planet’s surface. What is

the magnitude of the gravitational field strength

on the surface of the planet?

(1) 0.500 N/kg (3) 9.81 N/kg

(2) 2.00 N/kg (4) 61.3 N/kg

Verified Answer :

Boef

constant velocity means the netto force = 0, therefore F(gravity) = F(astronaut).
175N divided by 87,5kg = 2.00kg/N

Answer:

2.00 N/kg approximately.

Explanation:

A gravitational flied is defined as the quotient between the gravitational force and the mass:

\(g=\frac{F}{m}\)

Replacing all given values, we have:

\(g=\frac{175N}{97.6kg}\\ g=1.96\frac{m}{s^{2} }\)

Therefore, the gravitational filed is approximately 2.00 N/kg.

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