A circular path 2feet wide has an inner diameter of 150 feet . How much farther is it around the outer edge of the path than around the inner edge?

The circumference of any circle is
diameter x pi.

Distance around the outside of the walk is (150+2+2) pi = 154 pi feet.

Distance around the inside of the walk is 150 pi feet.

Difference = 4 pi feet.

Same as if you strung a string around the Earth that was 2 feet off the surface everywhere.

The string would be 4pi feet longer than the Earth's circumference at the surface ... about 12.5 feet.

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JeanaShupp JeanaShupp · Answer 2 · 2019-01-23T01:04:29-05:00

Answer: 12.56 feet

Step-by-step explanation:

Given: The width of the circular path= 2 feet

The inner diameter of circular path= 150 feet

Therefore, the inner radius of circular path=\(\frac{150}{2}=75\ ft\)

Now, the outer radius= 75+2=77 feet

We know that the circumference= \(2\pi r\)

Inner circumference= \(2\pi 75=150\pi\)

Outer circumference= \(2\pi 77=154\pi\)

The difference= \(154\pi-150\pi=4\pi=4\times3.14=12.56\ feet\)

Hence, the outer edge of the path is 12.56 feet farther than the inner edge