A system of equations is given below:


y = 4x − 3

2x + 7y = 41


Which of the following steps could be used to solve by substitution?


2(y = 4x-3) + 7y= 41


4x -3= 2x+ 7y


2x+ 7(4x- 3)=41


2(y= 4x-3)

Verified Answer :

Solving by substitution:

y = 4x - 3 

2x + 7y = 41

Let us substitute the first equation y = 4x - 3  into the second.

2x + 7y = 41

2x + 7(y = 4x -3) = 41

2x + 7(4x -3) = 41

So that's the third option.

I hope this helps.

TSO

y = 4x - 3
2x + 7y = 41

We need to substitute the first equation into the second equation. So, we would substitute y in the second equation with 4x -3.

2x + 7(4x -3) = 41

This would be answer choice C. 2x + 7(4x - 3) = 41.