How do you solve 2/3 (6n + 3) - (8c - 5)
\(\frac{2}{3} (6n + 3) - (8c - 5) \\ \\ \frac{2(6n+3)}{3} - 8c + 5 \\ \\ \frac{2 \times 3(2n + 1)}{3} - 8c + 5 \\ \\ \frac{6(2n+1)}{3} - 8c + 5 \\ \\ 2(2n+1) - 8c + 5 \\ \\ 4n + 2 - 8c + 5 \\ \\ 4n - 8c + 7 \\ \\ Answer: \fbox {4n - 8c + 7}\)
