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A car starts from rest and accelerates along a straight line path in one minute. It finally attains a velocity of 40 meters/second. What is the car's average acceleration?

A1.5 meters/second^2
B1.5 meters/second
C0.66 meters/second^2
D0.66 meters/second

Verified Answer :

skyluke89

The average acceleration of the car is given by:
\(a= \frac{v_f-v_i}{t}\)
where \(v_i\) is the initial velocity of the car, \(v_f\) is its final velocity and t is the time taken to attain the final speed. The car in the problem starts from rest, therefore its initial velocity is zero: \(v_i=0\). The final velocity is \(v_f=40 m/s\), while the time taken is
\(t=1 min= 60 s\)
Therefore, the average acceleration of the car is
\(a= \frac{40}{60} =0.66 m/s^2\)
and the correct answer is C.

Answer: The correct answer is 0.66 meters/second^2.

Explanation:

The expression for the acceleration is as follows:

\(a= \frac{v-u}{t}\)

Here, a is the acceleration, v is the final velocity and u is the initial velocity.

It is given in the problem that A car starts from rest and accelerates along a straight line path in one minute. It finally attains a velocity of 40 meters/second.

The time taken by a car is time, t= 1 min = 60 s.

Calculate the car's average acceleration.

Put t= 60 s, u= 0 and v= 40 m/s in the above expression.

\(a= \frac{40-0}{60}\)

\(a=0.66 meters/second^2\)

Therefore, the correct option is (c).

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