how do I solve x+2y=8
x+2y=82y=8-x |:2\(y=-\frac{1}{2}x+4\)y=ax+b ==> \(y=-\frac{1}{2}x+4\)We calculate the zeros of functions (0,b)(0,b) = (0,4)We have solution:x=0, y=4
If we put x = 0, we get0 + 2y = 8=> y = 8 / 2 = 4if we put y = 0x + 2 ( 0 ) = 8=> x = 8It means that solution set is { (0,4) , ( 8,0 ) }
