Answer: The volume of the gas at STP is 45.0 L. hence the correct answer is option(2).
Explanation:
Initial volume of the gas,\(V_1\) = 50.0 L
Initial temperature of the gas\(T_1\) =\(30.0^oC=30+273 K=303 K\)
\(0^oC=273 K\)
Final volume of the gas,\(V_2\) = ?
At STP, the value of temperature is 273 K.
Final temperature of the gas\(T_2\) = 273 H
Charles' Law: The volume is directly proportional to the temperature of the gas at constant pressure and number of moles.
\(V\propto T\) (At constant pressure and number of moles)
\(\frac{V_1}{T_1}=\frac{V_2}{T_2}\)
\(V_2=\frac{V_1\times T_2}{T_1}=\frac{50.0 L\times 273 K}{303 K}=45.0495 L\approx 45.0 L\)
The volume of the gas at STP is 45.0 L. hence the correct answer is option(2).
