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The dimensions of a brick that weighs 25 N are 0.19 m × 0.07 m × 0.095 m. What pressure does the brick exert on the ground if it is resting on its largest face?

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MattD

p - pressure [Pa] 
Fn - pressure force [N]
S - surface area [m²]
S = 0.19m*0.095=0.01805 [m²] (the two largest values ​​of bricks)
\(p=\frac{F_n}{S}=\frac{25N}{0.01805m^2}=1385[Pa]\)

Answer:

The pressure of the brick exert on the ground if it is resting on its largest face is 1385.04 Pa.

Explanation:

Given that,

Weight of brick = 25 N

The dimensions of a brick are 0.19 m × 0.07 m × 0.095 m.

The pressure of the brick exert on the ground if it is resting on its largest face.

So, The area of largest face of brick is

\(A = 0.19\times 0.095\)

\(A= 0.01805\ m^2\)

The pressure of the brick on the ground is

The pressure is the force upon area.

The formula of pressure is

\(P =\dfrac{F}{A}\)

\(P=\dfrac{25}{0.01805}\)

\(P = 1385.04\ Pa\)

Hence, The pressure of the brick exert on the ground if it is resting on its largest face is 1385.04 Pa.

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