Verified Answer :

The equation used to for slope intercept form is commonly used. 

y = mx + b

Let us find the y-intercept first.

The place where the line crosses the y axis is 2.

y = mx + 2

Now, find the slope.

Find two points on the line, then solve.

\(m = \frac{y2 - y1}{x2 - x1}\)

Alright, I found two points on the line:-  (-2,8) and (2, -4)

\(m= \frac{-4 - 8}{2--2}\)

m = -12/4
m = -3

The slope is -3. The y-intercept is 2

Lets put them into the equation

y = -3x + 2

Final answer:  
B.    y = -3x + 2

The equation that represents the line shown in the graph is:

B. y = -3x + 2

Further explanation

Solving linear equation mean calculating the unknown variable from the equation.

Let the linear equation : y = mx + c

If we draw the above equation on Cartesian Coordinates , it will be a straight line with :

m → gradient of the line

( 0 , c ) → y - intercept

Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :

\(\large {\boxed {m = \frac{y_2 - y_1}{x_2 - x_1}}}\)

If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :

\(\large {\boxed {y - y_1 = m ( x - x_1 )} }\)

Let us tackle the problem!

From the graph , the line goes through the point ( -1 , 5 ) and ( 0 , 2 ).

Let:

( x₁ , y₁ ) = ( 0 , 2 )

( x₂ . y₂ ) = ( -1 , 5 )

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We can calculate the gradient of the graph by using this following formula:

\(m = ( y_2 - y_1 ) \div ( x_2 - x_1 )\)

\(m = ( 5 - 2 ) \div ( -1 - 0 )\)

\(m = 3 \div (-1)\)

\(m = -3\)

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Next , we can find the equation of the graph by using this following formula:

\(y - y_1 = m ( x - x_1 )\)

\(y - 2 = -3 ( x - 0 )\)

\(y - 2 = -3x\)

\(y = -3x + 2\)

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Learn more

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Answer details

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

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