a 10N force is exerted on a box moving it 20m in the same direction what is the magnitude of work done on the box
The formula for work is
W = Fs
where W = work, F = force, s = displacement
Given that F = 10 N and s = 20 m, therefore
W = (10 N)(20 m) = 200 Nm = 200 J
Answer : Work done, W = 200 J.
Explanation :
Given that,
Force exerted on the box, F = 10 N
Distance covered by the box, d = 20 m
The angle between the force and the displacement is 0 as both are acting in same direction.
Work done on the box is given by :
W = F.d
\(W=10\ N\times 20\ m\)
W = 200 J
So, the work done on the box is 200 J.
Hence, this is the required solution.