Answered

A chemist dilutes a 1.0 mL sample of 2.0 M KNO3 by adding water to it. If the concentration of the solution that is obtained is 0.0080 M, what is its volume?

Use: Mi Vi = Mf Vf


A.) 125 mL

B.) 250 mL

C.) 500 mL

D.) 2,000 mL

Verified Answer :

Willchemistry

Mi = 2.0 M

Vi = 1.0 mL

Mf = 0.0080 M

Vf = ?

Mi Vi = Mf Vf

2.0 1.0 = 0.0080 Vf

2 = 0.0080* Vf

Vf = 2 / 0.0080

Vf = 250 mL

answer b

hope this helps!.

Answer: Option (B) is the correct answer.

Explanation:

The given data is as follows.

              \(M_{1}\) = 2.0 M,           \(V_{1}\) = 1.0 ml

              \(M_{2}\) = 0.008 M,         \(V_{2}\) = ?

Therefore, calculate the volume of given solution as follows.

              \(M_{1} \times V_{1}\) = \(M_{2} \times V_{2}\)

Now, putting the given values into the above formula as follows.

            \(M_{1} \times V_{1}\) = \(M_{2} \times V_{2}\)

            \(2.0 M \times 1.0 ml\) = \(0.008 M \times V_{2}\)

                   \(V_{1}\) = 250 ml

Therefore, volume of the solution obtained is 250 ml.

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