Answered

A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year, he earned $92 in interest. How much money was invested in each account?

A$1,500 at 2%; $2,300 at 4%
B$1,400 at 2%; $2,200 at 4%
C$1,000 at 2%; $1,800 at 4%

Verified Answer :

pepe11

x the first account  interest = x/1002 = 2x/100 
(x + 800)/100 4 =( 4x + 3200)/100 
2x/100 + (4x + 3200)/100 = 92
2x + 4x + 3200 = 9200 
6x = 6000
x = 1000
C is the answer

Answer: Option 'C' is correct.

Step-by-step explanation:

Since we have given that

Let the principal amount be 'x'.

First rate of interest = 2%

Second rate of interest = 4%

Number of years = 1

Amount of interest he earned = $92

According to question,

@@MATH_TOKEN_0@@

So, First investment of $1000 at 2% and Second investment of $1000+$800=$1800 at 4%.

Hence, Option 'C' is correct.

Related Questions