How many moles of hexane (C6H14) must burn to form 18.4 mol of carbon dioxide?
The combustion reaction of hexane:
2 C6H14 + 19 O2 = 12 CO2 + 14 H2O
2 mol C6H14 ---------> 12 mol CO2
x mol C6H14 ---------> 18.4 mol CO2
12 x = 18.4 2
12 x = 36.8
x = 36.8 / 12
x = 3.067 moles of CO2
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