Answer:
\(Pounds\ of\ ground\ meat\ use\ for\ the\ hamburgers\ is\ \frac{173}{80}\ pounds.\)
Step-by-step explanation:
As given
\(Keith\ bought\ a\ package\ with\ 2 \frac{9}{16}\ pounds\ of\ ground\ meat\ to\ make\ hamburgers.\)
i.e
\(Keith\ bought\ a\ package\ with\ \frac{41}{16}\ pounds\ of\ ground\ meat\ to\ make\ hamburgers.\)
\(He\ has\\frac{2}{5}\ pounds\ of\ ground\ meat\ left.\)
Pounds of ground meat use for the hamburgers = Total amount of meat Keith bought for make hamburgers - Amount of meat left
\(Pounds\ of\ ground\ meat\ use\ for\ the\ hamburgers = \frac{41}{16} - \frac{2}{5}\)
L.C.M of (16,5) = 80
\(Pounds\ of\ ground\ meat\ use\ for\ the\ hamburgers = \frac{41\times 5 - 2\times 16}{80}\)
\(Pounds\ of\ ground\ meat\ use\ for\ the\ hamburgers = \frac{205 - 32}{80}\)
\(Pounds\ of\ ground\ meat\ use\ for\ the\ hamburgers = \frac{173}{80}\)
\(Therefore\ pounds\ of\ ground\ meat\ use\ for\ the\ hamburgers\ is\ \frac{173}{80}\ pounds.\)
